And then there were none ?
Three doctors and three patients are traveling together through a jungle when they come to a river.
All the patients have a unique kind of fever which will infect the doctors if at any time the number of patients are more than the number of doctors.
The largest boat available can carry only two people at a time.
The doctors are immune if at any side of the river the body count of doctors are equal or greater than the numbers to patients. otherwise, the doctors gets infected. The doctors can only save the patients if they all reach together safely otherwise, "And then there were none" would be appropriate to say.
Time is running out. How will YOU save everyone's life ?
All the patients have a unique kind of fever which will infect the doctors if at any time the number of patients are more than the number of doctors.
The largest boat available can carry only two people at a time.
The doctors are immune if at any side of the river the body count of doctors are equal or greater than the numbers to patients. otherwise, the doctors gets infected. The doctors can only save the patients if they all reach together safely otherwise, "And then there were none" would be appropriate to say.
Time is running out. How will YOU save everyone's life ?
Labels: friday special, logic, puzzle, thinktank
posted by Rajesh Lal at
9:21 AM
30 Comments:
assign one patient to always be in the boat.
then take:
- doctor
- patient
- doctor
- patient
- doctor
you can either assign one patient to the boat at a time or one docter at a time and do what anonymous said^^
send two patients first, then two doctors, then doc and last patients
send two patients first, then two doctors, then doc and last patients
send two patiens, drop one off
patient returns and picks up another patient, drops him off
patient return and two doctors get in the boat, one is dropped off while a patient returns with the other doctor back the begining
so where are we...patient and doctor on first side, patient and doctor on other side, patient and doctor returning to first side in boat
patient gets out and two doctors go the other side
both doctors get out and send the one patient on their side back to pick up the rest of the patients
Send two patients in boat, drop off one, one returns. Count- one patient on other side, one patient in boat, three doctors and one patient on this side.
Patient picks up doctor and drops him off, then brings boat back.
Count- one doctor and one patient on other side, one patient in boat, two doctors and one patient on this side.
Patient gets out of boat, both doctors get in, one is dropped off on other side, while other doctor brings boat back.
Count- Two doctors and one patient on other side, one doctor in boat, and two patients on this side.
One patient joins doctor in boat. Doctor is dropped off on other side and patient returns for last patient.
Count three doctors and one patient on other side, one patient in boat and one patient on this side.
Patient picks up last patient, both get out on other side.
Count- three doctors and three patients on other side.
it said that the LARGEST boat available could carry 2 people..
so, they just have to take 3 boats, 1 patient and one doctor per boat..
=)
-2 patients
-2 doctors
-patient and doctor
times myself after i finished reading it, 6 seconds.
-> 2 patients
<- Boat comes back empty
-> 2 doctors
<- boats coems back empty
-> patient and doctor
cools
now the next question to 6 seconds guys is
HOW DOES THE BOAT COMES BACK EMPTY
dddhhh -
dddh hh} -
dddh {h h
ddh dh} h
ddh {h dh
hh dd} dh
hh {h ddd
h hh} ddd
h {h dddh
- hh} dddh
- dddhhh
h means patient, sorry :b
no one ever said they had to cross the river....
None of the solutions above is correct, because they assumed that as long as one person sits in the boat when it is at shore, it does not count. That is incorrect. The correct solution is the following:
DDPP DP}
DDPP {D P
DDD PP} P
DDD {P PP
DP DD} PP
DP {DP DP
PP DD} DP
PP {P DDD
P PP} DDD
P {P DDDP
PP} DDDPP
If you noticed, at no time when the boat is at shore, there are more patients than doctores.
i think the simpleist way is to take two patients
then two doctors
then the patient and the doctor
I DON'T GET IT!!!!! Could someone help me here? Maybe its u send a doctor and patient together *3
Each doctor kills his patient and then no one has to worry about getting infected.
don't go across the river, but if they must i say the doctors do what anonymous said ^ kill the patients that way their wouldn't be a problem.
All answers are bright but are NOT the answer to the question. READ... "And then there were none" would be appropriate.
Time is running out. how will YOU save everyone's life.
ok well you would first take two patients across then two doctors and then one doctor and one patient. yay!!!!!!!!!!
First you start out with one doctor, one patient. -Remember, doctors are immune if the number of doctors equals patients wherever they are- so...the doctor leaves the one patient, goes back gets another patient. this leaves two docs and one patient on the original bank, so they are immune. drop off the patient on the other side. doctor goes back to pick up a doctor, leaving one doc, one patient on the original bank. the two docs get off the boat, making it two docs, two patients. one patient goes back to pick up either the doc or the patient that is left, either way, everyone is safe. problem solved?
Its actually quite simple....
D- Doctor P-Patient
3D 1P ____ /boat/ ____ 2P
Then one patient comes back across and takes one doctor
2D 1P ____ /1P 1D/ ____ 1P
and you get
2D IP ____ /1P/ ____ 1P 1D
So the One patient takes across another doctor....
1D 1P ____ /1P 1D/ ____ 1P 1D
and you get
1D 1P ____ /1P/ ____ 1P 2D
Now take the other patient
1D ____ /2P/ ____ 1P 2D
and you get
1D ____ /1P/ ____ 2P 2D
And now the patient takes the last doctor across
____ / / ____ 3P 3D
AND THEN THERE WERE NONE!
EASY......
who says the doctors cant also be patients? each doctor can be a patient of one of the other doctors. so lets assume there are only 3 people there...
send 2 people across the river, one stays in the boat and goes back to get the third person
the people that said 2 patients then 2 doctors then 1 patient and 1 doctor are way off
who is driving the boat?!?!?
assign one patient to always be in the boat.
then take:
- doctor
- patient
- doctor
- patient
- doctor
that wouldnt work cuz when you take the doctor over there are 2 patients (although one is in a boat) and 1 doctor....
THATS NOT GOOD
:D
3D,1P----(2P)----->
3D,1P <--(1P)----- 1P
3D, ----(2P)-----> 1P
3D, <---(1P)----- 2P
1D,1P ---(2D)----> 2P
1D,1P <--(1D,1P)-- 1D,1P
2P ---(2D)----> 1D,1P
2P <---(1P)---- 3D
1P ----(2P)---->3D
1P <---(1P)---- 3D,1P
----(2P)---->3D,1P
I got something similar to the one who started:
3D 1P ____ /boat/ ____ 2P
but I don't think any of the ones before that were correct... remember the part about needing more doctors than patients? -- that's why the ones that have the 2 passengers stay there or have them bring over the third right away don't work... but I wrote mine up like this: (maybe patient1 will die from exhaustion, but it was quick and dirty)
1 pat1 rows and pat2 lands
2 pat1 rows and doc1 lands (pat2 and doc1) (pat3 and doc2,3 left)
3 pat1 rows and doc2 lands (pat2 and doc1,2) (pat3 and doc,3 left)
4 pat1 rows and pat3 lands (pat2,3 and doc1,2) (doc3 left)
5 doc3 rows for pat1 -- both land.(and then there were none?)
so... in order: P D D P PD
I suppose the only 'twist to the rules' I assume here is that the patient that's rowing can stay in the back of the boat while the third doctor gets on so they don't 'infect' him.
Let's assunme there is a driver for the boat, you send a doctor and a patient each time and the boat goes across 3 times. Quite simple.
This one is quite similar-
There's a man with a wolf, a sheep, and a sack of corn. He is travelling across the countryside and arrives at a river. To cross the river he must use the ferry. Weigh restrictions allow only two to cross at a time, which includes the sack of corn. Problem is, if the wolf is left with the sheep, it will eat the sheep. If the sheep is left with the sack of corn, it will eat the corn. The sun is setting and the ferry will close soon. Thinking fast, he figures out a way to get the wolf, the sheep, and the sack of corn to the other side.
Can you?
Too easy!
Take the sheep leaving the wolf with the corn. Drop off the sheep and go back to pick up the sack of corn and take it to the other side, while there get the sheep and take it back across with you. Once there leave the sheep, get the wolf and take it across, leave it with the sack of corn. Go back and get the sheep and return to the side you were heading to. Now all are on the other side.
Will this one every be answered?
ANSWER
--------------------------
DDDPPP - {none}
DP =>
DDPP - DP
D <=
DDDPP - P
PP =>
DDD - PPP
P <=
DDDP - PP
DD =>
DP - DDPP
DP <=
DDPP - DP
DD =>
PP - DDDP
P <=
PPP - DDD
PP =>
P - PPDDD
P <=
PP - PDDD
PP =>
{none} - PPPDDD
GOT RIGHT
--------------------------
14th anonymous guy from top
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