Tuesday, November 6, 2007

Odd person out

I was at a party with a friend one evening where he got bored and started keeping track of the number of handshakes made by people. A person was called "odd person" if he made an odd number of handshakes, otherwise he was called "even person".

After some time my bored friend said to me, "Hey, do you know that there are an even number of odd persons?" I replied, "Big deal ! there will be always an even number of odd persons". But still he seemed confused ?

Can you explain in one line , why this is so ?

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32 Comments:

Anonymous Anonymous said...

test

November 6, 2007 10:27 AM  
Anonymous Anonymous said...

because theirs only two people.

November 6, 2007 12:39 PM  
Anonymous Anonymous said...

not because there are only two people, but because it takes two people for a handshake.

November 6, 2007 4:19 PM  
Anonymous Anonymous said...

This post has been removed by a blog administrator.

November 6, 2007 6:01 PM  
Anonymous Anonymous said...

2 odds make an even in addition

November 6, 2007 6:33 PM  
Anonymous Fardin said...

anonymous guy one above looks more confused than rajesh's friend who is counting the handshakes hahahaha !

November 6, 2007 9:12 PM  
Anonymous Anonymous said...

odd personS, it is plural meaning more then one.. besides, it takes two p/p to shake hands

November 6, 2007 9:23 PM  
Anonymous Anonymous said...

3rd Anonymous comment is right:

Everyone starts at zero handshakes, 2 people shake giving 2 'odd people'. Carrying on to infinity, there will always be an even number of odd people since it will always be +2, -2, or +0 'odd people'

November 6, 2007 10:58 PM  
Anonymous Anonymous said...

Oh, and in answer to the real question: No, I can't do it on one line.

November 6, 2007 10:59 PM  
Anonymous Anonymous said...

Here's the concept: two people shake hands, both shook ONE hand, you end up with two "odd people".

November 7, 2007 5:41 AM  
Anonymous Anonymous said...

there is an even number of ppl in room, each person shakes odd amount of hands, if theres 4, then 4ppl shake 3 hands

November 7, 2007 1:46 PM  
Anonymous Anonymous said...

what if he shakes hands with himself????????

November 7, 2007 2:00 PM  
Anonymous Anonymous said...

Then he becomes a 'very odd person'.

November 7, 2007 5:24 PM  
Blogger Chuma said...

Ha! That's rich! I can't explain it in one line. But...when an odd person shakes with an odd person, they both become even, so the number of odd people decrease by two. When an even person shakes with an even person, they both become odd so the number of odd people increase by two. When an odd person shakes with an even person, the odd becomes even and the even becomes odd, so the total number of odd people stay the same.
The comment about 'very odd person' was very good, though!

November 7, 2007 9:10 PM  
Blogger Judy said...

This post has been removed by the author.

November 9, 2007 8:06 AM  
Blogger Judy said...

(It didn't come out right in the above post so let me try again)

If I am in a room with 9 other people, that makes 10 of us, an even number of people. We all shake hands with the other 9 people in the room, making an odd number of handshakes.

And this would be reversed if the number of people in the room was an even number. Then there would be an odd number of handshakes.

November 9, 2007 8:09 AM  
Anonymous Anonymous said...

is he asking why he was confused?

because an even number of odd people is a hard sentence to wrap your mind around?


foochaz

November 9, 2007 8:35 PM  
Anonymous Anonymous said...

What if one person in the room didn't shake hands with everyone else???

November 11, 2007 4:08 AM  
Blogger Judy said...

This post has been removed by the author.

November 11, 2007 5:58 AM  
Blogger Judy said...

(Again, I find something wrong in my initial post and have to do it again...sort of odd number of posters with even number of posts! LOL)

Now don't go confusing the issue Anonymous. ;-D

This could go either way. I tried it a couple ways, using 10 people...here goes.

10 ppl in room and 1 person shakes 4 hands...all others shake all remaining hands
1 > 4 (odd # of evens)
5 > 8 (odd # of evens)
4 > 9 (even # of odds)

Also,
10 ppl in room and 1 person shakes 3 hands...all others shake all remaining hands
1 > 3 (odd # of odds)
3 > 9 (odd # of odds)
6 > 8 (even # of evens)

So I supposed if you 'insist' on making things difficult, you could probably make it any combination...but basing it on 10 ppl shaking everyone else's hand, the even # of odds still stands.

But, the correct answer is still supposed to be in ONE LINE, so my answer is incorrect either way you look at it. :-(

November 11, 2007 6:03 AM  
Anonymous Janel said...

odd numbers added always equal even numbers

November 11, 2007 12:12 PM  
Anonymous Anonymous said...

It takes two people to make a handshake.

November 11, 2007 4:34 PM  
Anonymous Anonymous said...

This is becasue x is an even number and y is the amount of handshakes they can make, y has to equal x-1!

November 11, 2007 11:53 PM  
Anonymous Anonymous said...

there has to be 2 people to shake hands

November 13, 2007 7:02 AM  
Blogger Daniel said...

I didn't really take the time to go through and read all of the comments, so forgive me if I'm repeating someone's answer.

That said, there will always be an even number of odd persons, in any room:

There are three types of handshakes:

Even-even, Odd-odd, and Even-odd.

In an even-even handshake, two people who are "even people" shake each other's hand, both becoming "odd people", thus increasing the number of "odd people" by two, and not changing the evenness of the number.

In an odd-odd handshake, the opposite happens, both odd people become even people, and the number of odd people decreases by two, still not changing the evenness of the number.

And finally in an odd-even handshake, the two people switch roles, giving zero net change.

In review, after every handshake the number of "odd people" in the room can only change +2, -2, or +0 with a single handshake.

Since at the start of the event all people are "even people" (0 handshakes) and there are zero "odd people," the number will always be even.

November 13, 2007 11:16 AM  
Blogger Daniel said...

D'oh! Can you explain it in one line?

At the start of the party the number of "odd people" is even, and through every subsequent handshake the number increases by two, decreases by two, or stays the same and all these three changes maintain evenness.

Sorry about that :)

November 13, 2007 11:19 AM  
Blogger Rajesh Lal said...

ANSWER
-----------------------------
Total Number of handshakes (EVEN) = Sum of Handshakes of Even Persons (EVEN) by definition + Sum of Handshakes by ODD Persons (Has to be EVEN)* ,because EVEN = EVEN + EVEN


Detail
-----------------------------
* Because you cannot add odd numbers, odd number of time to get an even number, So the total number of Odd persons has to be EVEN to make the sum of handshakes EVEN, Only assumption here is you are not counting the handshake with yourself

GOT RIGHT
-----------------------------
A FEW OF you were close, the question was a bit tricky to capture in one line

Chuma, judy and daniel's analysis were reasonabaly close

November 13, 2007 11:23 PM  
Blogger Josh A. said...

Daniel has it right, just over explained.

November 15, 2007 10:02 PM  
Anonymous Anonymous said...

you cant shake your own hand.

if there are 20ppl then they each shake 19 hands.

November 22, 2007 5:31 PM  
Blogger Peji said...

it's not necessarily true.

You, him and me in the party. I shake your hand:

2 odd people, 1 even person

I leave because the party is not going to get any better than this..

1 odd person, 1 even person


-Peji

November 24, 2007 12:04 PM  
Anonymous Anonymous said...

nice catch peji. but if u wanna look at the other side of it lol, the guy thats at a party with only one other person is pretty odd himself, unless its a bedroom party with a secret password.

November 25, 2007 5:49 PM  
Anonymous Anonymous said...

This post has been removed by a blog administrator.

June 26, 2008 1:35 AM  

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