"Simple" Multiplication
Here is a simple multiplication , and believe me you can solve this
x is a symbol of multiplication. The puzzle is to subsitute P, Q, R, S, T, & M with unique integers to make the above equation true.
P Q R S T
x M
----------
T S R Q P
x is a symbol of multiplication. The puzzle is to subsitute P, Q, R, S, T, & M with unique integers to make the above equation true.
Labels: mathemagic, trickofmind
posted by Rajesh Lal at
9:37 AM
15 Comments:
m=1
every other integer may vary. as long as m=1 the product of the problem will have the same variables.
21978
x4
------
87912
the problem with yours HWDIV is that if i do x * 1, im going to get x. So if x is 25, 25 *1 is 25, not 52
Wow I feel dumb. I was going through x2-x4 and seeing which numerals would reverse their digits' numeral in each scenario (i.e, 4x3=12; is 2x3<=4? no...).
When I got to x4, I said "2x4=8, so 2 might be in the 10,000...but 8x4=24, so it doesn't work..."
I learned my multiplication tables 17 years ago. But clearly it didn't stick.
10001
x1
-----
10001
Maggie, i don't believe your answer is correct. PQRST all seem to be different variables therefore for yours to be correct it would have to be something like:
PQQP
xP
-----
PQQP
Ydrameos has the right idea.
M*T=P, M*S=Q, M*R=R, M*Q=S, M*P=T.
Solve for each variable, you get;
T=P/M, S=Q/M, R=R/M, Q=S/M, P=T/M.
[(T/M)(S/M)(R/M)(Q/M)(P/M)]
x M
---------------------------
T S R Q P
the only reason that i am bringing up my education is to prove a point...
i use to feel good about getting my doctorate in physics, but after reading this and the posts.. i feel as dumb as a box of rocks..lmao... very good answer Erica...
im thinking X=M :)
My solution is this:
00000
* 0
------
00000
easy as Cake!
(cake>pie)
2,1,0,-1,-2 (X) -1
11111
x1
-----
11111
Would be the correct answer or all 0's
ANSWER
----------------
21978
x 4
------
87912
GOT RIGHT
----------------
ydrameos, Erica (good analysis)
11111
x1
______
11111
The puzzle is to subsitute P, Q, R, S, T, & M with UNIQUE integers to make the above equation true.
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