Analog Clock
You have an analog clock with an hour, minute and second hand. What time is it when all 3 hands are "exactly" evenly spaced (120 degrees apart).
-Euclid's Brother
-Euclid's Brother
Labels: SharedPuzzle
posted by Mr Fahrenheit at
4:14 PM
15 Comments:
where is at least one of the hands?
12:20 and 45 seconds
12:20 and 40 seconds
8:00 and 20 seconds if it were 12:20 the hour hand wouldnt be exactly on the 12 and therefore the hands wouldn't be exactly 120 degrees apart from eachother.
2hr 55min and 35 sec
the gap would be 120degrees in a circle
exactly at 4:00:40.
Everyone who said that it was on an hour mark for the hour and/or minute and/or second hand is most likely wrong. Like the answer given by the user named "me" it can't be on an hour mark for two hands.
there is no definite answer. There is an infinite number of possibilities because it did not states if the hands are forced to be on a number on the clock.
all that matters is that they are 120 degrees apart. Therefore, since you can always go smaller when it comes to numbers such as I second can be 0.5 seconds which can be 0.25 seconds and so on.
there is no answer; or the answer is infinity
umm there are many many variations but it does end somewhere....
It must be 4:40:00 Michael
Yeah i have to agree...
The second(hand) must be on 00 seconds...
there are hunders of possibilitys u need to give one of the clock hands away so the other 2 hands would be placeed exactly to have just 1 answer
There is no exact time when that occurs..
The answer above 2:55:35 is probably as close as you can get using whole seconds.. but at the time, the hour hand is on 2.92638888888889, the minute hand is on 55.5833333333334, and the second had on 35. So the angle between minute and second had is at least 120.5 degrees.
I've written a program that steps the clock in increments of .00001 seconds and even rounded to the nearest 1000th. And still there is not exact time that works..
its dumb cus it can be a bunch of different things
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