Timeless puzzle
"Boss."
"Yes Tom."
"How long did you take to get home from the office?"
"Well, when I started from the office the hour hand and the minute hand were together and when I got home they had just about got exactly opposite each other."
"And Boss."
"Go on. Tom"
"Had you left the office when the two hands were exactly opposite each other, you would have got here exactly when the two met."
"I don't know, Tom"
Sharp Tom did manage to get the Boss muddled up, but was he right ?
"Yes Tom."
"How long did you take to get home from the office?"
"Well, when I started from the office the hour hand and the minute hand were together and when I got home they had just about got exactly opposite each other."
"And Boss."
"Go on. Tom"
"Had you left the office when the two hands were exactly opposite each other, you would have got here exactly when the two met."
"I don't know, Tom"
Sharp Tom did manage to get the Boss muddled up, but was he right ?
Labels: friday special, logic, thinktank
posted by Rajesh Lal at
8:46 AM
16 Comments:
Tom is pretty sharp.. In both cases, it takes the boss approx 33.5 minutes (actually just a hair longer. prolly like 33.56 minutes or so).. But it doesn't matter both cases take the same amount of time.
In 30 minuntes, the minute had would travel 180 degrees. But the hour had would have traveled 15 degrees, so the minute hand would have to travel another 15 degrees to be nearly opposite hour hand.
Same is true for the second case.
got me muddled up for sure,
- Fardeen is back
Gawd ! where does this guy gets his questions from.
are they at the office when the question is asked?
if so, then the answer is no, because if he left the office when the hands were opposite, he would have gotten back to the office, any time he darn well pleased
other than that, (lol, I actually tried this out on a clock) let's start at 12:00, when they were opposite it would be 12:32, so 33 min. therefore, to take the same amount of time, it would be 1:06. it would have to be 1:05 for them to be together, so i'd say it was close enough
I definetely agree with the guy above me, Euclid's brother you're abit off and when it says it is opposite, it doesn't say it was the same time when he left at opposite and he got home at opposite, lol i don't know the answer, but just putting it out there
It doesn't matter what time he leaves either place. It takes approx 33 mins each direction. 30 minutes will have the minute hand travel 180 deg and the hour hand travel 15 deg.. so the minute hand has to travel that 15 deg (approx 3 minus) to be either on top, or oppisite, whichever the case is..
The start time is irrelevent, the clock is anlog and the movement ratio between the minute hand and the hour hand is constant.
oh! so the puzzle is Timeless. :)
To figure out how many minutes from parralel to opposite, you count the minutes between the minute hand and where it will end up. Then you add that many 11ths of minutes for the distance the hour hand moved. Trust me, after using complicated equations in trigometry I discovered this simple way to do it.
Example:
It is three o'clock. How long until the hands are pointing in the same direction?
It will be fifteen minutes until the minute hand reaches the three, and another fifteen elevenths until the minute hand catches up with the hour hand. So 15 15/11, or 16 5/11.
I haven't gotten any of these problems wrong since.
but... if it's 3 o'clock, then the hands aren't opposite, they're at 90 degrees. Don't bother with math just try it out on an actual clock
the answer is yes, and i think thats all there is to it.
Hmmm these people don't live in LA. It doesn't take the same time if you leave at 3:00 or 3:30. It may take 2 and a half hours (plus 6 min/hour) .vs. 30 minutes depending on when you leave.
It is a trick question, and the answer is maybe, maybe not. If it was twelve when he left, it may have beenaround one thirty-six, not twelve thirty. And if the driving was better, he may have left when the hands were opposite and gotten there in about half an hour.
The three o'clock example was just an example to demonstrate the math used to determine that it takes the same amount of time for the hands to go from opposite to parallel as parallel to opposite.
wat the hell im confused and im just a blonde!!!! :) lol im not that funny!!
please just give me a question i know how to do
No tom is wrong!
The boss said he left when the two hands were touching and got home right before they were opposite ( making the trip aprox 29 mins). Then tom asked if the boss left home when the hands were exactly opposite and then got to work when the hands were exactly touching (making the trip aprox 30 mins). This is not the same time because in the first statment the hands werent touching so the time is different by a minute or two!
i think tom is right..
anyway, where is the ans...zzz
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