Car Auction
A man is going to an antique car auction. All purchases must be paid for in cash. He goes to the bank and draws out $25,000.
Since he does not want to be seen carrying that much money, he divides the money between fifteen envelopes labeled 1 through 15. Each envelope contains the least number of bills possible, for example, instead of two tens there would be a twenty, instead of two fives there would be a ten, etc.
At the auction he makes a successful bid of $8322 for a car. He hands the auctioneer envelopes 2, 8, and 14.
After opening the envelopes the auctioneer finds exactly the correct amount.
The amount of money in each envelope is mathematically related to the number on the envelope, with envelope 15 being an exception.
The question is; how many one dollar bills did the auctioneer find in the three envelopes?
-Matthew Lauser
Since he does not want to be seen carrying that much money, he divides the money between fifteen envelopes labeled 1 through 15. Each envelope contains the least number of bills possible, for example, instead of two tens there would be a twenty, instead of two fives there would be a ten, etc.
At the auction he makes a successful bid of $8322 for a car. He hands the auctioneer envelopes 2, 8, and 14.
After opening the envelopes the auctioneer finds exactly the correct amount.
The amount of money in each envelope is mathematically related to the number on the envelope, with envelope 15 being an exception.
The question is; how many one dollar bills did the auctioneer find in the three envelopes?
-Matthew Lauser
Labels: mathemagic, SharedPuzzle
posted by Mr Fahrenheit at
3:12 PM
10 Comments:
pretty sure this question was posted a while back...
so scott whats the answer then,,
-smell my pubes
no idea, as that involves sifting back through all the other probs, and i really don't have that kind of energy
Its either 2 or 0 because you either have a one dollar bill in two envelopes or a two dollar bill in one evenlope to get the two dollars at the end
Well, "mathematically related" could mean anything, any two values are mathematically related in some sense, but supposing the envelops' numbers are factors of the amounts of money within, the answer must be 0, because 2, 8 and 14 are even numbers.
I'm with Alexander.
The answer is one. The amount of money in each envelope equals 2^(# of envelope - 1).
So envelope 2 has $2, a $2 bill.
Envelope 8 has $128, a 100, 20, 5, 2, and 1.
Envelope 14 has $8192, 81 100's, a 50, two 20's, and a 2.
How's that for a hard puzzle?
now that is as fun as Watt moving his pebbles. But just as meshuggeh. Right answer, wrong pockets or wrong pockets left answer?
no math in this one. if any 2, because the rest is always trying to do the biggest bills.
its 0 because its says he only uses big bills.
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