Outside the Box
There are five boxes A,B,C,D, and E each with some oranges in it.
1. Box A has 12 times oranges than in B
2. Oranges in D is 1/2 as in A, and is equal to the product in B & C
3. E, with mid number, is the sum of oranges in C & 1 other box
4. Number of oranges in C is number in A divided by 8
5. One of the boxes contains 4 oranges
Can you find out the numbers ?
1. Box A has 12 times oranges than in B
2. Oranges in D is 1/2 as in A, and is equal to the product in B & C
3. E, with mid number, is the sum of oranges in C & 1 other box
4. Number of oranges in C is number in A divided by 8
5. One of the boxes contains 4 oranges
Can you find out the numbers ?
Labels: friday special, logic, mathemagic
posted by Rajesh Lal at
8:28 PM
4 Comments:
ummm, hey wats a mid number?
anyways
A=48
B=4
C=6
D=24
E=10
...i think.....
-yurka
well i know one
E=MC2
A = B * 12
D = A / 2
D = B * C
E = C + ? (E is mid number)
C = A / 8
? = 4
============================
B = 4 (a hunch based off 1st line)
A = 48
C = 6
D = 24
E = 10
And it all works out.. ;)
We're actually given more information than we need. Statements 1, 2 and 4 give us 4 equations with 4 variables, leading to B=4, C=6, D=24, A=48. Statement 3 tells us E=C+B=10, otherwise E would not have a middling value.
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