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Can you arrange four Eights in such a way that they total exactly 100 ?
Labels: mathemagic
posted by Rajesh Lal at
11:56 AM
Monday, May 12, 2008
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5 Comments:
I think maybe its (8/.8)*(8/.8)
That would be 10*10
100
Yay, first post!
This is the only thing I can come up with...
(8/.8) * (8/.8) = 100
-Euclid's Brother
i dont get it:S
88/.88
At first I misunderstood, and because of that I decided to make it into an equation using 4 eights like in a problem using x=8, then solving for y.
x^3+y / x =100
Where 4 8s can be used
8^3+y / 8 =100
8*8*8 + y / 8 =100
512+y=800
y = 288
so 8^2 + 288/8 = 100
64+36=100
But I had no idea that I could arrange it in any way so that 88/.88=100. So thanks
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