Peculiar Groups
Mrs. Connar wrote the following letters in the board
1 2 3 4
5 7 8 9
and said to the class.
"I want you to arrange the eight numbers I have written on the board into two groups of four numbers each. When you add up each group, the sums must be the same.
Your time starts now."
1 2 3 4
5 7 8 9
and said to the class.
"I want you to arrange the eight numbers I have written on the board into two groups of four numbers each. When you add up each group, the sums must be the same.
Your time starts now."
Labels: mathemagic, outside-the-box, trickofmind
posted by Rajesh Lal at
8:10 AM
20 Comments:
If your supposed to add them together, i dont think there is a way.
Or can you multiply/divide/subtract too?
she has nine numbers which eight r u suppoae to add
there are only 8 numbers (she didnt write 6) but since the total of all the numbers is an odd number (39) there cannot be two groups of the numbers that each add up to the same number--so i think its impossible too, unless they misworded the riddle...
1289
3
7
5
4
THEY BOTH ADD UP TO TWENTY.
3+7+5+4 = 19
Now if it was a six instead of a five that would work.
Did you misword the riddle or are we missing something? Cause there is no way to get those eight numbers in two groups that add up to the same amount.
how about:
12 + 5 + 7 = 24
3 + 4 + 8 + 9 = 24
is that allowed?
It has to be groups of 4
This post has been removed by the author.
8
2945
7
3
The total of the numbers is 39, so it is impossible to get two groups of four numbers that add up to the same. As stated earlier, someone messed up the riddle. 12, 5, and 7 in one group is only three numbers, not four. Unless you can reuse each number, there is no solution. If you can reuse each number, then the solutions are limitless.
well if the number was a 6 instead of a 9 the 1st group would be 3,5,8,2 and the 2nd group would be 1,3,6,and 7 both group equal 18
is that "ur time starts now" comment relevant in any way?
if everyone took the time to notice TRICK of mind means these are trick questions the key word is ARRANGE the groups into 4 numbers you just happen to arrange the 1 and the 2 next to each other so the groups are
1257
3489
2 groups of 4 numbers now add
12+5+7=24
3+4+8+9=24
the trick is on paper 12 is actually two seperate numbers.
There appears to be 2 distinct solutions of the same group (does the teacher give extra credit for figuring out both?)
29+58=87
73+14=87
or
28+59=87
13+74=87
My answer would be:
9+8+7-4=20
(3-1)*5*2=20
try this:
1 8 2 7 = 18
3 6 4 5 = 18
(invert the 9)
3 + 9 + (1/2) = 12.5
5 + 7 = (4/8) = 12.5
It is almost impossible to have a sum just by adding, so maybe she meant that it is supposed to be done by subtracting, etc.
Why Did the Riddle Say "Letters?"
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