1996
complete the following maths problem by filling the blanks using only the symbols listed afterwards:
1__9__9__6__=10
symbols: * , / , + , - , ( , ) , ! , squareroot
you may use more than one symbol per space provided eg 1 multiplied by the squareroot of 9 and the numbers must remain in their given order, enjoy and ill post answer in... 5 days
daniel
1__9__9__6__=10
symbols: * , / , + , - , ( , ) , ! , squareroot
you may use more than one symbol per space provided eg 1 multiplied by the squareroot of 9 and the numbers must remain in their given order, enjoy and ill post answer in... 5 days
daniel
posted by Mr Fahrenheit at
7:39 AM
16 Comments:
((1+9)*(squareroot(9))!)/6=10
((10)*(3!)/6=10
(10*6)/6=10
60/6=10
10=10
1+9/squareroot9+6=10
Drake
1+9/squareroot9+6=10
Drake
1+(9/(squareroot9))+6
1+9+((squareroot9)!)-6=10
all doing great, just so you know i have 7 proven answers which i wont bother posting but keeping trying, these more out there.
first anon
drake
lesley
all got 1 each but i count atleast 4 more. id like to see how many there are so keep posting.
1+SQUAREROOT(9)+(9-6)!=10
1+3+3!=10
4+6=10
10=10
1+9*((squareroot(9)!/6)=10
1+9*(3!/6)=10
1+9*(6/6)=10
1+9*1=10
1+9=10
10=10
(1+9)*((squareroot(9)!/6)=10
10*(3!/6)=10
10*(6/6)=10
10*1=10
10=10
1+9-((squareroot9)!-6)=10
10-(3!-6)=10
10-(6-6)=10
10-0=10
10=10
That's 4 more.
Here's another one:
1+9*((squareroot9)!-6)!=10
10*(3!-6)!=10
10*(6-6)!=10
10*0!=10
10*1=10
10=10
And another:
1+9*((squareroot(9)!/6)!=10
1+9*(3!/6)!=10
1+9*(6/6)!=10
1+9*1!=10
1+9*1=10
1+9=10
10=10
And another:
(1+9)*((squareroot(9)!/6)!=10
10*(3!/6)!=10
10*(6/6)!=10
10*1!=10
10*1=10
10=10
Just add any number of !'s to 1 to get 1.
Or add any number of squareroots to 0 or 1 to keep them the same.
Oh, and the comment I made 2 spots above about 1! also applies for 2.
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