Car mechanics
My mini is 3.05m in length, and the body sits 0.3m off the ground.
Unfortunately the exhaust is cracked right in the centre of the car.
Assuming I can only lift the car at either end or I risk damaging the bodywork, and that I need a clearance of 0.5m to work under the car, how high do I need to jack up the car and which end would be best to use.
Unfortunately the exhaust is cracked right in the centre of the car.
Assuming I can only lift the car at either end or I risk damaging the bodywork, and that I need a clearance of 0.5m to work under the car, how high do I need to jack up the car and which end would be best to use.
posted by pramsay13 at
5:01 AM
9 Comments:
This question can't be answered. The tire (front,back) will act as a fulcrum and will be the point at which an angle will form. Without knowing the distance from one tire to the opposite bumper the math can't be completed.
Using similar triangles the problem can be completed. You know the body is .3m of the road, the working area needed is .5m so the distance to where the angle would be formed is .915m. The total distance the car needs to be jacked up is 1.3 m. Since the end in question is already .3m off the ground it has to be jacked up an additional 1m. I'd jack it up from the back because of the engine being in the front... there is less mass to lift in the rear. for reference the angle I got between the road and theoretical continuance point of the undercarriage is 18.1527 degrees.
If you don't know what you're doing, you should really leave this type of work up to professionals. Have your mechanic do the work - you don't want to risk cracking the frame and doing more damage.
hahaha
i think Roger H was serious in his comment or possibly being extremmely sarcastic
Well Being a mechanic myself, the easiest thing to do is get the car on the ramps, then both sides come up at the same time, or if you need to work on the floor, then jack up the back so the exhaust doesnt get damaged on the floor as the car is so low, put axle stands in place, then jack up the front and add more axle stands, if more height is needed then go to the baack, jack up some more and adjust the axle stands, then repeat on the front, but thats a personal prefferance lol
Gee
You lift it from the front. Why? Because that's how you get a car towed. (I think :P) Then, at the mechanic's, you let him/her do what they were trained to do. Give them measurements like that, and they'll laugh.
.4 meters.
You need only consider the property of a slope or the ratio of similar triangles.
The midpoint needs to come up .2 meters. As the origin of the angle (since you dont need the pythagorean theorem to solve this, the actual distance between the fulcrum and rising bumper doesnt matter) never increases in height and the opposite bumper increases the most, the midway point between the two would increase at a rate exactly between the rate of the two points (in other words, half of whatever the rising bumper raises). Since you need to raise the midpoint an additional .2 m to reach the .5 m requirement, you therefore must raise the bumper .4m.
this is easy. u need to raise just 0.2m up as it is 0.3m off the round. so u would gt a total of 0.5m of clearance. both ends would do as a mini is proportional in size.
ok so the crack in in the middle of the car and the car is 3.05 meters long so i first divided that by two. Then i took this information and used the Pythag therom. a^2+b^2=c^2. so a = the 3.05 divided by 2 which is 1.525. The b = the .5 meters that you have to raise car to be able to work on the crack in the center. So you square both of those and add them. Then you take the square root of your answer and you get about 1.6. Take that and subtract .3 meters for the origional heighth of the car and you get 1.3 meters. This how high you would have to raise the rear of the car. You would not want to raise front because that is where the engine is.
~Mateo~
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