Tuesday, September 9, 2008

The driver and the C.E.O.

Every day, a driver leaves the office, drives to the house of the C.E.O to pick her up and drives back to the office. One day, the C.E.O. decides to leave 1 hour early and walks along the same route that the driver takes. When the driver sees the C.E.O. walking, he picks her up and returns directly to the office. The C.E.O. notes that she has arrived 20 minutes earlier than normal. How long did she walk?

-posted by Euclid's Brother

Labels:

15 Comments:

Anonymous Fardin said...

REPOST

September 9, 2008 12:03 PM  
Anonymous Anonymous said...

same old puzzle with a new coat of paint

September 9, 2008 12:47 PM  
Anonymous Euclid's Brother said...

sorry.. havn't seen it here before..

September 9, 2008 1:20 PM  
Anonymous Euclid's Brother said...

ahh.. i see it now.. it was posted when i was on vacation last month.. I havn't read all those yet.. :(

September 9, 2008 2:05 PM  
Anonymous Anonymous said...

logic, she was supposed to save an hour, since she saved only 20 mins, she walked for the rest, ie. 40 mins.
since driving time remains constant

September 9, 2008 2:30 PM  
Anonymous Euclid's Brother said...

last anon.. nope.. not right.

September 9, 2008 2:57 PM  
Anonymous Squeeky said...

there is not enough information to slove the problem, we need the distance to her house and the speeds they travel at.otherwise it is just guess work, with no mathematical logicbehind it.

September 9, 2008 5:57 PM  
Anonymous Meelad said...

well, since she got there 20 minutes early to work, that leaves us with 40 minutes. In that forty minutes, she walked and got a ride. So she probably walked for at least 20 minutes, in order to be 20 mintues early. If you say she walked for 40 mintues, then she got there on time, not 20 minutes early. Because 20+40=1 hour. So it has to be 20+20=40=20 minutes early.

Answer therefore= 20 minutes.

September 10, 2008 12:14 AM  
Anonymous Anonymous said...

she walked the distance that it would take the car 10 minutes to drive.

~Cybersurf~

September 10, 2008 12:15 AM  
Anonymous Euclid's Brother said...

no correct answers yet.. but cybersurf is closest... just need to know the number of minutes she walked..

And yes, there is enough information to determine the number of minutes..

September 10, 2008 7:15 AM  
Anonymous Euclid's Brother said...

I also read the puzzle posted last month that is just like this one.. no one answered it correctly either, nor did the poster come back and post the correct answer.

September 10, 2008 7:19 AM  
Anonymous Anonymous said...

She was walking for 50 minutes. The logic behind this is that the driver cut 20 minutes off of the time it takes for him to get from point a to point b. That means 10 minutes going to her house and 10 minutes coming from her house. Since she had already left an hour early, and he was on his way to pick her up, you can get the amount of time.

September 10, 2008 9:18 AM  
Anonymous Euclid's Brother said...

yep..your right. 50 minutes..

The driver met her 10 minutes drive time from her house. Thus saving 20 mins from car trip. Therefore, she was picked up 10 minutes prior to her normal pickup time. So she had to have walked for 50 minutes.

September 10, 2008 10:46 AM  
Anonymous fewbear said...

well if she left an hour early she will have walked amost an hour before her driver see's her so i am going to say 55 min's and it was a five min drive to work from there and since she cut his drive time down considerably it would of only been a short drive back to the office. so it's either 55 min's or an hour that she walked.

September 12, 2008 6:20 PM  
Anonymous Anonymous said...

it's 30 minutes.

if she got there 20 mins early that means that the driver would normally take 40 minutes for a round trip...20 there and back.
he only had to go half the distance though..which would be 10...
60-20-10=30

30 minutes....

October 4, 2008 7:53 PM  

Post a Comment

Links to this post:

Create a Link

<< Home