Mysterious Six
In mathematics the number six can be achieved by using any number three times with mathematical expressions.
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
Let me do one for you , 2 + 2 + 2 = 6. Now can you try the rest ?
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
Let me do one for you , 2 + 2 + 2 = 6. Now can you try the rest ?
Labels: bcreative, mathemagic
posted by Rajesh Lal at
2:09 AM
13 Comments:
* = multiplied by. / = divided by
111
i cant find it
222
2+2+2 (as mentioned)
333
3*3-3 (9-3)
444
sqrt4+sqrt4+sqrt4 (2+2+2)
555
5/5+5 (1+5)
666
6/6*6 (1*6)
777
7^2-7/7 (42/7)
888
cuberoot8+cuberoot8+cuberoot8 (2+2+2)
999
(sqrt9)!/(sqrt9)!*(sqrt9)! (3 factorial, so multiply by all number before it, 1*2*3=6. 6/6*6 or 1*6)
Maybe an advance on the above:
111: (1+1+1)! = 3! = 6
777: 7-7/7 = 7-1 = 6
888: 8 - sqrt(sqrt(8+8)) = 8-2 = 6
(doesn't need cube roots)
999: sqrt(sqrt9) x sqrt(sqrt9)
+ sqrt9
= sqrt3 x sqrt3 +3 = 3+3 = 6
Chris
(1+1+1)! = 3! = 6
Never would have guessed to use factorial notation...
I figured out 1 1 1
(1+1+1)! (factorial)
Don't forget 0 and 10 to complete the 1-10 (though it wasn't explicitly asked for)...
0 (B2!+B2!+B2!)!
= (1+1+1)!
10 (SQRT(B12))!
= (3.16)!
According to my calculator (3.16)! is 7 point something.
To get to 6 from three 10s:
(int(sqrt(10+10-10)))!
= (int(3.16))! = 3! = 6
Chris again
Alternative:
9: (9 + 9) / SQRT(9)
Clarification:
0: (0! + 0! + 0!)!
lol some of mine were slightly more complex than necessary
(3squared + 3squared)/ 3 = 6
(4cubed/4squared) + sqr4 = 6
(5/5) + 5 = 6
(6 - 6) + 6 = 6
7 - (7/7) = 6
(8cubed/8squared) - cuberoot8 = 6
(9 + 9)/sqr9 = 6
to Surge:
0! technically equals 1, according to math textbooks. Theoretically I don't know how that works.
6 can be done 3 ways
6-6+6 --> (6-6)..[0]+6 = 6
OR
6x6/6 --> (6x6)..[36]/6 = 6
OR
6/6x6 --> (6/6)..[1]x6 = 6
6+6-6--> (6+6)..[12]-6 = 6
Someone email me and explain the factorial notation.. idget it.. =[
tropicana_is_a_dinosaur@hotmail.com
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