Number Cruncher
So the number X is of three digits and it is divisible by 11. With one more condition that X/11 is equal to sum of the squares of the digits of X.
What is X, won't be a surprise question will it ?
What is X, won't be a surprise question will it ?
Labels: mathemagic
posted by Rajesh Lal at
11:07 AM
15 Comments:
The answer is 50.
I meant 550. RBW
990
132
803
550 and 803 are both accurate answers here
yep
I found two solutions, 550 and 803
hjg
I'm guessing--440
550 definietly works
1+4i. Just kidding, I got the same as you guys.
44 could work.
Oh, nvm, i just saw that it has to be 3 digits. :(
xoxo
Bre
550/11=50
550=>5*5+5*5+0*0=25+25=50
803/11=73
803=>8*8+0*0+3*3=64+9=73
AvWG
Can't 440 work?
NO 440 is not a valid answer, so stop asking. 440/11=40, but 4^2+4^2+0^2=32, NOT 40
The same goes for
132:
132/11=12, but 1+9+4=14
990/11=90, but 81+81+0=162
To sum it up, it's ok to be wrong, but don't continually ask if the wrong answer is right. It takes very little mathematical skill to show that 440 is NOT a valid answer.
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