Poles and Fence II
If the average distance between post is 15 feet.
and the necessary area per cow is .4 cows per acre.
How many cows could he have?
Reference previous question, "Poles and Fence"
and the necessary area per cow is .4 cows per acre.
How many cows could he have?
Reference previous question, "Poles and Fence"
posted by Ragknot at
7:50 AM
5 Comments:
FIRST POST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Wow, its been a while since I last did that.
N E way, I think it's 0.
Yep, still a loser.
Anyways, each length of the area (square) is 390 feet (26 lengths * 15 feet). So the area is 390 *390 = 152,100 square feet. One acre is 43,560 square feet. So the cow pasture is 3.4917 acres. If each cow needs .4 acres, than it is 3.4917/0.4, meaning you can have 8.729 cows per acre.
But seeing how you can't have a partial cow, and you can't round up because there isn't enough room, you can only have 8 cows in your fenced in area.
but if his wording is correct and youre allowed .4 cows per acre then it would be 3.4917*.4= 1.3967 cows...therefore rounding down gives only 1 cow
Yes Thrym you are right. I just read right over that thinking the opposite, because who deals with 4 tenths of a cow, unless you are a butcher. And if that is the case, that is an awful lot of room for just one cow.
Most everyone is on the right track. Cows eat grass, which is generally low on food value, and cows are big creatures and need a lot of grass. On ranches where the grass normal, it may take 20 to 80 acres to feed one cow.
Which brings up my point, the first puzzle about "Polls and Fence", said a farmer is building a fence around his cows. Post as generally placed at 10 -15 foot intervals, and even with a great pasture, his fenced area area could not carry more that 1 or maybe 2 cows.
Post a Comment
Links to this post:
Create a Link
<< Home