Do you Know Gambling
With two dice getting a total of X is more likely than Y.
Can you tell for what value of X and Y this is true ?
Can you tell for what value of X and Y this is true ?
Labels: mathemagic, thinktank
posted by ToM at
9:22 AM
4 Comments:
I'm finding it difficult to interpret the problem clearly. You seem to be implying there is a unique X and Y.
From memory, the most probable total when throwing two die is 7, and this I take to be the "best" X. So Y could be any of the other possible totals: 2 to 6 and 8 to12.
True, SEVEN is the most likely total. Anything BUT seven is less likely.
From the other end, 2 and 12 are the least likely totals, so they are the "best" Y. All other totals are more likely.
There are obvious in between X's and Y's.
I'm still not sure that I've really understood the problem. Maybe I'm looking for something that isn't there.
Probabilities of getting each dice sum:
2 = 1/36
3 = 2/36
4 = 3/36
5 = 4/36
6 = 5/36
7 = 6/36
8 = 5/36
9 = 4/36
10 = 3/36
11 = 2/36
12 = 1/36
If X > 7 you are more likely to beat Y
If X < 7 you are more likely to loose to y
Comment posted by:
Vincent Jumper
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