Mixing it
You have jugs A and B that contain the same amount of differing liquids. Take a small sample from A and mix it into B. Then take the same size sample from the A+B mix and mix it into A. What is the relative concentration of A in B to B in A?
There's more than one way of solving this.
There's more than one way of solving this.
Labels: funphysics, mathemagic, SharedPuzzle
posted by Chris at
1:25 PM
7 Comments:
The relative concentrations of A to B and B to A are the same in each jug.
You're right. How did you do it?
Was it you who did the xth root of x too?
How did I do it? Just by logic. If you have the same volumes in each jug before and after then any amount of B in jug A must be matched by the same amount of A in jug B.
Yes, I did the xth root one too. I live in Australia and seem to find that I get first go at a lot of these puzzles when I get up in the morning. Maybe they should be posted at different times of the day to give the rest of the world a chance at first go!
That is a very nice bit of logic.
I hadn't researched it before posting. I just remembered it from a long time ago. I hope I would have thought of it (eventually).
I'm in the UK, but keep West Coast USA hours. Anyone can post from anywhere in the world. But you do need to get a Googlemail account first.
You must check out the bug on a band problem. It's the nicest one I've seen in ages. I fancy you could have done that one. Greetz
Chris and 1st anon is right.. They will have they same (or oppisite rather?) ratio.
JugA ration will have some ration of lA:lB and JugB will have the same ration lB:lA (l = liquid)
This was actually posted here I think about 10 or 12 months ago but was about red wine and white wine.
Please forgive all the typos above.. "ratio" and "opposite"
Hi EB. LOL. Yes I know, I posted the problem. LOL again.
I didn't know that had been posted. I haven't looked at many of the archives yet.
All typos are hereby forgiven.
You got a lot of Brownie points for helping me crack the "bug on a rubber band". Greetz.
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