Friday, August 28, 2009

Treasure Revisited

The solution to the original post (yesterday) was to quick.
But we can hopefully find the numeric solution with some given data.

Let's say the Elm tree is at (30,35) and the Oak is at (80,44).
These are x,y coordinates.

Find the x,y of the treasure within a 1/2 unit.

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28 Comments:

Blogger Chris said...

This post has been removed by the author.

August 28, 2009 12:23 PM  
Blogger Chris said...

Ragknot, I guess you like finding treasure :)

August 28, 2009 12:31 PM  
Blogger Chris said...

I could cheat and use Miguel's answer from the other one.

August 28, 2009 4:12 PM  
Blogger Alexander said...

Falcon! Eggplant! Rise & shine!!!

August 28, 2009 5:32 PM  
Blogger Ragknot said...

Chris,

I see the solution that seems the easiest to me. But it seems that it gives two solutions.

1. connect the trees with a line.
2. from the midpoint of the line, draw a circle that passes thru both trees.
3. The solution is the where a perpendicular thru the midpoint
intersects the circle.
4. But there's two intersections.


I can't see how the left, right from the instructions help find which one is the solution, without
using a point as the gallows.

August 28, 2009 8:33 PM  
Blogger Chris said...

You must define where the gallows is, otherwise the instructions can't be obeyed and then you haven't got a left and right.

August 28, 2009 8:54 PM  
Blogger Chris said...

...you only have to define the gallows mentally, then mentally obey the instructions, which you can do in a few seconds. It'll then be obvious which is the correct intersection to choose.

If the elm is at 9 o'clock, the oak at 3 o'clock, then the treasure is at 12 o'clock. Strangely enough, the clock hand does scale distances as well.

August 28, 2009 9:07 PM  
Blogger Ragknot said...

You would think that someone could work the math, with the numbers.

August 28, 2009 11:51 PM  
Blogger Chris said...

This post has been removed by the author.

August 29, 2009 3:15 AM  
Blogger Chris said...

Just to show how wonderfully useful complex numbers are for plane
geometry, I'll use Miguel's result from the other problem.

Let E, K and T denote the location of the Elm, the Oak and the
treasure respectively. Miguel proved that T = (K+E - i(K-E))/2.

In this case E=30+35i and K=80+44i.
So T=(110+79i-i(50+9i))/2 = (110+79i-50i+9)/2 = (119+29i)/2

So the treasure is located at (59.5, 14.5). Thank you Sqrt(-1).

August 29, 2009 3:21 AM  
Blogger Miguel Tato said...

Bingo! :)

August 29, 2009 7:53 AM  
Blogger Chris said...

Hi Miguel, I was impatient, I should have let you do it.

August 29, 2009 8:20 AM  
Blogger Miguel Tato said...

A small variant I just invented: if we know the position of the Gallows, the Elm and the Treasure, what is the procedure to find the Oak? Not mathematically (too obvious), but using instructions like in the original problem (counting paces, turning right or left, etc.).

August 29, 2009 8:23 AM  
Blogger Miguel Tato said...

No prob Chris... :)

August 29, 2009 8:24 AM  
Blogger Chris said...

Walk from E to T counting steps. Turn right and walk same number of steps :)

August 29, 2009 8:59 AM  
Blogger Chris said...

This post has been removed by the author.

August 29, 2009 9:03 AM  
Blogger Chris said...

This post has been removed by the author.

August 29, 2009 9:11 AM  
Blogger Chris said...

Miguel, Soz, that was too sneaky of me:) I'll try with G explicit.

August 29, 2009 9:20 AM  
Blogger Miguel Tato said...

You're right, Chris. In fact, it is easy to demonstrate that i(T-K)=T-E, and so:
a) T-K and T-E have the same length, and
b) T-K and T-E are normal (they make 90ยบ)

So, your answer is correct :)

August 29, 2009 9:25 AM  
Blogger Chris said...

This post has been removed by the author.

August 29, 2009 10:03 AM  
Blogger Chris said...

I hope Ragknot doesn't mind us doing this. I'll abbreviate it to save verbiage.
Walk G to E, turn right, walk same distance, now at P1.
Walk P1 to T, keep going (same distance) mark P2.
Walk to G, counting steps, then halfway back to P2, turn right, walk same again as you just did, to K.
Plant an acorn.

August 29, 2009 10:31 AM  
Blogger Miguel Tato said...

yep, that was my solution too. but when you posted your first I tried it and you were right: that's the best we can do :)

August 30, 2009 9:36 AM  
Blogger Ragknot said...

Chris,

Of course I don't mind. I wanted discussion and exploration.

Since I did not give a point for the gallows, I expected two solutions. Did any one give two solutions? I gotta check.

August 30, 2009 12:42 PM  
Blogger Chris said...

Thank you Ragknot. I just felt that Miguel and I, were perhaps a little too far off topic.

August 30, 2009 1:01 PM  
Blogger Chris said...

This post has been removed by the author.

August 30, 2009 2:27 PM  
Blogger Chris said...

This post has been removed by the author.

August 30, 2009 2:33 PM  
Blogger Ragknot said...

When I draw this points and select a gallows point, I get the treasure is at (50.5,64.5)
If I switch the left/right, I get the (59.5,14.5).

maybe I remembered the left / right backward?

August 30, 2009 4:39 PM  
Blogger Chris said...

My bad. I typed a sign wrong. Should have checked on a diagram.
Here's the corrected workthrough:

Let E, K and T denote the location of the Elm, the Oak and the
treasure respectively. Miguel proved that T = (K+E + i(K-E))/2.

In this case E=30+35i and K=80+44i.
So T=(110+79i+i(50+9i))/2 = (110+79i+50i-9)/2 = (101+129i)/2

So the treasure is located at (50.5, 64.5). Thank you Sqrt(-1).

Part 2
I hope I've got this right:
Let M be the mirror location.
Then the mid-point, C=(T+M)/2
But this is the same as the centre point of the Elm and the Oak
So C=(E+K)/2. Equating and rearranging => M=E+K-T
=>M=30+35i+80+44i-50.5-64.5i

Mirror at (59.5,14.5)

August 30, 2009 5:23 PM  

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