Two trouble
posted by ToM at
7:39 AM
Thursday, September 17, 2009
Links
Search
Share
- Tom Chrome Extension
- ToM @ Twitter
- MeeT ToM
- Daily Tricks Widget
- Vista Gadget 1.5
- iPhone Widget
- Windows XP Widget
- Google Toolbar Button
- Suggestions
Favorite Links
- Vista Sidebar Gadgets
- Widgets for Web 2.0
- C Sharp Tricks
- Interview Information
- Illustrator - Elar Alexander
Bookmark Us
Previous Posts
- Star Trek
- Return to WowDVDFilm
- Favorable Bet
- Heads or Tails?
- Phasers on stun
- 17 (camels)
- You're kidding!
- Wow, DVD Film
- Humphrey Thou Sand
- Even upside down?
7 Comments:
Taking a serious liberty, if work mod 18, then 2 / 10 = 2 (mod 18)
=> 2 = 20 (mod 18) and that is true.
I might be back ^^
(a-b)^2=(b-a)^2
If a=1 and b=1/10,
(1-1/10)^2=(1/10-1)^2
Taking the square root,
1-1/10=1/10-1
Adding 11/10 to both sides,
2/10=2
LOLOL... Quite a cheating, huh?
Just saw the correct answer. Too farfetched, could never get it by my own. And so, I prefer mine ;)
Miguel, I think your answer is more like it. Very clever manipulation.
I just Googled it too. Other answer is rubbish compared to Miguel's. So I won't post it.
It is easy to generalize this fake demonstration to proove any equality. For example to proove that e=pi,
(e-pi)^2=(pi-e)^2 =>
=> e-pi=pi-e => e=pi
If I have some time, I'll try to find a way to "cover up" a little bit the cheating step...
Hi Miguel, I hadn't knowingly seen that particular set of moves before. You handle it like a pro. I doubt that you can hide the cheat easily while retaining the elegance.
Post a Comment
Links to this post:
Create a Link
<< Home