Wednesday, January 27, 2010

Horses and a Will

Seventeen horses are to be divided among three sons, according to a man's will. The will states the oldest son gets 1/2 of the horses, the middle aged son gets 1/3, and the youngest gets 1/9. An obvious solution involves horse meat for dinner ... but the sons agree they do not want to harm their father's horses.

How did they divide the horses and still comply with the stipulations in the will?

8 Comments:

Blogger David and Kimmy Wright said...

It woulds seem to me the easiest way to do this would be to borrow a horse from a friend. Then the oldest son would get 9 horses(18/2) the 2nd 6(18/3) horses and the youngest 2(18/9) horses
9+6+2 = 17
The borrowed horse can then be returned to its owner

January 27, 2010 9:52 AM  
Anonymous Zaux said...

are you kiddin' me? ... why would you use such an approach? ... however, it is the right approach ... heh heh ... good job

January 27, 2010 9:56 AM  
Anonymous Zaux said...

This post has been removed by a blog administrator.

January 27, 2010 9:58 AM  
Anonymous Karl Sharman said...

Actually, I would disagree...

I would institute a breeding programme, and the moment the first mare foals, equally divide up the horses according to dearly departed daddy's will.

January 27, 2010 10:05 AM  
Anonymous Zaux said...

what if the horses had no romantic intentions toward one another?

January 27, 2010 11:25 AM  
Blogger Chris said...

This post has been removed by the author.

January 27, 2010 11:47 AM  
Blogger Chris said...

Unfortunately, the father's will cannot be honoured.

After the divvy up and returning the borrowed horse, the eldest would have 9/17, the middle 6/17 and the youngest 3/17 of the original herd.

But that's OK as it's a trick question.

January 27, 2010 11:48 AM  
Blogger Chris said...

... and there should have been been 1/18 of the herd left over.

January 27, 2010 11:50 AM  

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