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Friday, January 15, 2010

Find a 2 digit number, with identical digits, such that when it is multiplied by 99, the product has a 5 as the 3rd digit from the left.

Antn'y said...: 44*99=4356, so 44 works.; January 15, 2010 2:40 PM
Ragknot said...: 66 * 99 = 6534

The 3rd digit FROM the LEFT is 5

44 gives the 2nd digit from the left as 5.; January 15, 2010 3:41 PM
Chris said...: LOL, Ragknot, you don't know your left from your right.; January 15, 2010 3:59 PM
Ragknot said...: ah, I am embarrassed.; January 15, 2010 4:18 PM
Zaux said...: Hey Ragknot ...if I change the problem statement, you'd be right ...; January 15, 2010 4:29 PM
Chris said...: ... or if you didn't know your left from your right.; January 15, 2010 4:31 PM
Chris said...: OR in Ragknot's case he'd be left.; January 15, 2010 4:31 PM
Anonymous said...: going to resort to brute force since i only need to perform 9 multiplications
11*99=1089 fail
22*99=2178 fail
33*99=3267 fail
44*99=4356 WIN!
55*99=5445 fail
66*99=6534 fail
77*99=7623 fail
88*99=8712 fail
99*99=9801 fail

Answer:
44 FTW
Cam; January 15, 2010 7:19 PM
Chris said...: It's curious that Ragknot's answer was the reversal of the correct answer.; January 15, 2010 7:25 PM