Sunday, January 17, 2010

Merry-Go-Round

Whilst riding on a Merry-Go-Round, ToM noticed that the total number of riders was equal to one-third of those ahead of him plus three-quarters of those behind him. How many riders were there?

7 Comments:

Anonymous Anonymous said...

# riders =x
since merry go round is circle (x-1) riders, ahead or behind

ahead+behind+Tom=all riders
1/3*(x-1)+3/4(x-1)+1=x

1/3*x+3/4*x-1/3-1/4+1=x
13/12*x-1/12=x
x=1

Shocking only Tom is on the ride....


Did I err ?

Cam

January 17, 2010 7:16 PM  
Blogger Chris said...

I like your answer better than the correct one.

January 17, 2010 7:21 PM  
Anonymous Anonymous said...

Found the mistake !

# riders =x
since merry go round is circle (x-1) riders, ahead or behind

ahead+behind+Tom=all riders
1/3*(x-1)+3/4(x-1)=x

1/3*x+3/4*x-1/3-1/4=x
13/12*x-13/12=x
-13/12=-1/12*x
x=13

13 are on the ride

Cam

January 17, 2010 7:25 PM  
Anonymous Knightmare said...

13
on a merry-go-round,the person right ahead of you can still be behind you.

January 17, 2010 7:30 PM  
Blogger Chris said...

Luckily for you both, 13 isn't an unlucky number this time.

January 17, 2010 7:43 PM  
Anonymous SpArKo said...

1/3 (x-1)+ 3/4 (x-1) + 1= x
(1/3 + 1/4) (x-1) + 1 = x
13x -13 + 1= 12x
x= 12

January 18, 2010 3:45 AM  
Blogger Chris said...

Hi SpArKo. You've made three mistakes. The +1 on your first line shouldn't be there. You changed 3/4 to 1/4 on your second line, but that was merely a typo. You forgot to multiply the erroneous 1 by 12 for your third line.

January 18, 2010 5:05 AM  

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