A Trick Question Every Day
posted by Zaux at 9:05 PM
R1-R2=6V1-V2=R1^3-R2^3=504V1-V2=(R2+6)^3-R2^3V1-V2=(R2+6)^2*(R2+6)-R2^3V1-V2=(R2^2+12*R2+36)(R2+6)-R2^3V1-V2=(R2^3+12*R2^2+36*R2+6*R2^2+72*R2+216)-R2^3V1-V2=18*R2^2+108*R2+216=50418*R^2+108*R2-288=0quadratic formula applies to find 0sR=(-b+/-sqrt(b^2-4*ac))/(2*a)R=(-108+/-sqrt(108^2+4*18*288))/(2*18)R=2,-8Discard -8, as side must have positive lengthSide length of R2=2R1 has side length of 8Check answersR2-R1=8-2=6R1^3-R2^3= 512-8=504Answer:The larger cube has side length of 8, and volume of 512The smaller cube has side length of 2, and volume of 8Cam
Nicely done ...
Thank's Zaux. Nice problem. Thank you for posting it. Cam
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3 Comments:
R1-R2=6
V1-V2=R1^3-R2^3=504
V1-V2=(R2+6)^3-R2^3
V1-V2=(R2+6)^2*(R2+6)-R2^3
V1-V2=(R2^2+12*R2+36)(R2+6)-R2^3
V1-V2=(R2^3+12*R2^2+36*R2+6*R2^2+72*R2+216)-R2^3
V1-V2=18*R2^2+108*R2+216=504
18*R^2+108*R2-288=0
quadratic formula applies to find 0s
R=(-b+/-sqrt(b^2-4*ac))/(2*a)
R=(-108+/-sqrt(108^2+4*18*288))/(2*18)
R=2,-8
Discard -8, as side must have positive length
Side length of R2=2
R1 has side length of 8
Check answers
R2-R1=8-2=6
R1^3-R2^3= 512-8=504
Answer:
The larger cube has side length of 8, and volume of 512
The smaller cube has side length of 2, and volume of 8
Cam
Nicely done ...
Thank's Zaux. Nice problem. Thank you for posting it.
Cam
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