Friday, January 1, 2010

Sides of Two Cubes

The difference between the sides of two cubes is 6, and the difference in their volumes is 504.

Find the sides of the cubes!

3 Comments:

Anonymous Anonymous said...

R1-R2=6
V1-V2=R1^3-R2^3=504

V1-V2=(R2+6)^3-R2^3

V1-V2=(R2+6)^2*(R2+6)-R2^3
V1-V2=(R2^2+12*R2+36)(R2+6)-R2^3
V1-V2=(R2^3+12*R2^2+36*R2+6*R2^2+72*R2+216)-R2^3
V1-V2=18*R2^2+108*R2+216=504

18*R^2+108*R2-288=0

quadratic formula applies to find 0s
R=(-b+/-sqrt(b^2-4*ac))/(2*a)

R=(-108+/-sqrt(108^2+4*18*288))/(2*18)

R=2,-8
Discard -8, as side must have positive length

Side length of R2=2

R1 has side length of 8

Check answers
R2-R1=8-2=6
R1^3-R2^3= 512-8=504

Answer:
The larger cube has side length of 8, and volume of 512
The smaller cube has side length of 2, and volume of 8


Cam

January 1, 2010 10:33 PM  
Anonymous Zaux said...

Nicely done ...

January 1, 2010 10:45 PM  
Anonymous Anonymous said...

Thank's Zaux. Nice problem. Thank you for posting it.

Cam

January 2, 2010 7:32 AM  

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