Squared Sets
In a set containing 3 numbers, each is squared, the squares are added, and the total is 139.
In another set containing 6 numbers, each is squared, and added for a total of 139.
(a number may appear in both sets)
Identify and list both number sets.
In another set containing 6 numbers, each is squared, and added for a total of 139.
(a number may appear in both sets)
Identify and list both number sets.
posted by Zaux at
5:50 PM
9 Comments:
set 1: 9, 7, 3 ( 81+49+9=139)
set 2: 2, 3, 4, 5, 6, 7
gotta love trial and error ;)
Hi Paddy ... you are right
nice ... uh, trial and error... heh heh
9+49+81=139
4+9+16+25+36+49=139
Also
1+4+9+25+36+64=139
9,9,121
1,4,9,9,16,100
I'm taking set rather loosely
1+ 16+ 25+ 25+ 36+ 36= 139
4+ 9+ 16+ 25+ 36+ 49= 139
1+ 1+ 16+ 36+ 36+ 49= 139
9+ 9+ 16+ 16+ 25+ 64= 139
1+ 4+ 9+ 25+ 36+ 64= 139
1+ 1+ 1+ 36+ 36+ 64= 139
4+ 4+ 9+ 9+ 49+ 64= 139
1+ 9+ 16+ 16+ 16+ 81= 139
4+ 4+ 9+ 16+ 25+ 81= 139
1+ 1+ 4+ 16+ 36+ 81= 139
1+ 4+ 9+ 9+ 16+ 100= 139
Nice one Ragknot. I assume that there aren't (m)any more for sets of three. Would I be right (or wrong)?
6.244997998398398, 7.745966692414834, 6.324555320336759 so the possibilities are endless (never mentioned what type of numbers)
You people are too smart for me.
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