Saturday, February 13, 2010

1 thru 6

Using the digits 1,2,3,4,5 and 6 only once,can you fill in the blanks?


??*?=???

3 Comments:

Anonymous Anonymous said...

54*3=162

Cam

February 13, 2010 5:45 PM  
Blogger Knightmare said...

yep

February 13, 2010 5:49 PM  
Anonymous Anonymous said...

for ab*c=def
-we can eliminate 1 from being b or c
since the f would be a duplicate
-we can eliminate 5 from being b or c as f would be 0 or 5 (duplicate or 0 which is invalid)

Look at other groups of bc which are candidates:
2*3=6
2*4=8 no 8 invalid
2*6=12 dup 2 invalid

3*4=12
3*6=18 no 8 invalid

4*6=24 dup 4 invalid

so only b,c of (2,3) or (3,4) are candidates

look at 3,4
13*4=52 too small
23*4=92 too small
53*4=212 dup 2
63*4=252 dup 2

14*3=42 too small
24*3=72 too small
54*3=162 WINNER!
64*3=192 9 invalid


look at 2,3
12*3=36 too small
42*3=126 dup 2
52*3=156 dup 5
62*3=186 8 invalid

13*2=26 too small
43*2=86 too small
53*2=106= 0 invalid
63*2=126 dup 2

Thus 54*3=162 is the only valid answer.

Cam

February 13, 2010 6:33 PM  

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