3,2,1 blast off ...
Two rockets are aimed such that they will just miss each other. They are launched simultaneously. The rockets are programmed to land at each others launch point. They will travel the same distance ... horizontally and vertically. At the point of flight where the 2 rockets pass each other, one takes one additional hour to reach its destination and the other takes nine more hours.
How much is one rocket's velocity faster than the other?
How much is one rocket's velocity faster than the other?
posted by Zaux at
2:35 PM
7 Comments:
You didn't tell us that the two rockets took off simultaneously, so this can't be solved...
OK, I'll assume you just left that out, and continue struggling.
Hi ross ...
I believe the second sentence states a simultaneous launch ...
:-) thanks man ... I added it.
A........X...B
rocket A travels AX in t hours
and BX in 1 hour
and AB in t+1 hours
rocket B travels BX in time t
and AX in 9 hours
and AB in t+9 hours
[1] Va*t = Vb*9
[2] Vb*t = Va*1
divide equation 1 by 2
Va/Vb = 9*Vb/Va
Va^2/Vb^2 = 9
Va/Vb = 3
Ross ...
take another look at it ... you solved it so quickly, you didn't let everyone else have any fun :-)
good job man ... 3 times as fast is the winner
Sorry ... I am just so bored with work right now ... I'll leave the next dozen problems to others
Hi Zaux and Ross. I used to find the decision about when to post very difficult. I used to wait at least 24 hours, but the urge to post is irresistable. So, I just post when I feel like it, or when it's convenient. My 20p.
Hey Ross ...
just kidding man ... solve all of them ...
I never thought it would be so difficult to continue to find problems worthy of the level of skill on this site ... I was wrong. Sometimes I present a puzzle thinking it will be up for days and the first post has the solution. I salute the problem-solving skills of ToM's participants ... outstanding!
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