Buses
Five buses are traveling along a road.The two in the front and the two in the rear are holding a total of 84 people.The middle bus has four people less than the average of all five.How many passengers are in the middle bus?
posted by Knightmare at
7:09 PM
19 Comments:
16
Bus 1 21.00
bus 2 21.00
Bus 3 ======= 16.00
Bus 4 21.00
Bus 5 21.00
total 84.00
average 20.00
let a,b,c,d,e be the numbers of passengers in each bus.
Average A = (a+b+c+d+e)/5 = (84+c)/5
But c = A - 4, so A = (84 + a - 4)/5
=> A = 16 + A/5 => A = 20 => c = 16
So the average is 20, and the middle holds 16. Cannot say much about the distribution of passengers in the other four buses.
no winners yet
T=total
T/5=average
Middle bus=T/5-4
84+(T/5-4)=T
80+1/5*T=T
80=4/5*T
T=5/4*80
T=100
T/5-4=100/5-4=16
Answer:16
Above is mine. But I guess, Knightmare says we are all wrong ?
Cam
woohoo...i got 3 pros!
16 people on the bus:
15 passengers + 1 driver
Answer: 15
Cam
now you got it Cam
Coises. Cam's spotted your evil trickery.
Chris...better keep on you toes ;]
coises?
"Coises, foiled again" - I think it was said by Snidely Whiplash (a sort of Dick Dastardly character).
oh no...here we go with more new words-my mind is full already!
Wow, Cam
talk about a "trick".
Ha, Ha, good one.
This post has been removed by the author.
This post has been removed by the author.
Did anybody yet posted the right answer?
My calculation says the answer is 15 passengers in the middle bus.
Let the middle bus have x people.
So (84+x)/5= x+4
x=16.
So total number of passengers are 84+16= 100
However, it could be that out of 16 people, 1 be driver so number of passengers in middle bus are 15 or 16, whatever u wanna take.
Knightmare. "coises" is "curses" with a Brooklyn accent.
SpArKo. Cam did it. 15 passengers is the answer.
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