Chris's English Comprehension Test
Old and Young's ages total 48 years.
Old is twice as old as Young was, when Old was half as old as Young will be, when Young is three times as old as Old was, when Old was three times as old as Young.
How old is Old?
(just reading that ... :) ... gives me a headache ...)
Old is twice as old as Young was, when Old was half as old as Young will be, when Young is three times as old as Old was, when Old was three times as old as Young.
How old is Old?
(just reading that ... :) ... gives me a headache ...)
Labels: wordfun
posted by Zaux at
6:54 PM
3 Comments:
Trying to figure it out logically is impossible (okay, not really :P)! Good one, was too tired for maths, so trial and error it is.
Would appear that Young is 18 and Old is 30? Should be right. 12 year difference.
Backwards:
Old was 18, Young was 6
Young will be 3x18=54
Old was 0.5*54=27 and Young was 27-12=15
Old is 2x15=30.
Gosh I wasted a lot of good notepad here :P Good one, good one. Totally agree on the headache, that's for sure :D
Hi Pingy ...
you are right
I got another solution for that.
Follows an equation per statement, sorted chronologically (x for old, y for young):
(1) x1 = 3y1, diff = x1 - y1
(2) y2 = 3x1
(3) x2 = 0.5y2, y3 = x2 - diff
(4) x3 = 2y3
And given that:
(5) x3 + y4 = 48
(6) x3 > y4
Solving the set of equations together, we get that:
x3 = 5y1 ---->(a)
From (5),
5y1 > y4
5y1 > 48 - 5y1
10y1 > 48
Hence, y1 > 4.8 ----> (b)
Substituting into (5),
5(y1 > 4.8) + y4 = 48
Hence, y1 < 10 ----> (c)
Setting any value for y1 in (b), and substituting back in (a) and (5) gives us the answer.
From (b) and (c), the possible answers are:
x3 = 25, y4 = 23 ; y1=5
x3 = 30, y4 = 18 ; y1=6
x3 = 35, y4 = 13 ; y1=7
x3 = 40, y4 = 8 ; y1=8
x3 = 45, y4 = 3 ; y1=9
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