It's how hot?
As a new resident of Puzzlaria, Chris is not familiar with the two most commonly used temperature scales. The scales bear no resemblance to the Farenheit, Centigrade, and Kelvin scales with which he is familiar.
He is told by Ragknot that 14⁰ in the first system is equal 36⁰ in the second. Also he is informed that 133⁰ in the first is 87⁰ in the second.
What is the formula for converting one system temp. to the other?
At what temp. will both thermometers read the same?
He is told by Ragknot that 14⁰ in the first system is equal 36⁰ in the second. Also he is informed that 133⁰ in the first is 87⁰ in the second.
What is the formula for converting one system temp. to the other?
At what temp. will both thermometers read the same?
posted by Zaux at
4:01 PM
6 Comments:
Before I am assualted with comments that my degree symbol is not perfect ... I am aware ... does anyone where the degree symbol is in Character map?
Chris ... received the message from ya ... it's me ... it really is! :-)
Hiya Zaux. That's a relief.
The degree symbol is the first character in the set below. It doubles up (more or less) as a superscript 0.
º¹²³αβγδΔεζηθξρσφλμπωΣΩΓ»«☺♠♣♥♦♪♫ћ√∞≈≠≡≤≥‖│ ¼ ½ ¾ ⅓ ⅔ ⅛ ⅜ ⅝ ⅞ ₁ ₂ ₃ ₄
Thanks Chris ... superscript 0 would work .. didn't thinnk of it.
Assume both scales are linear.
At absolute 0, 0K the scales will be their base constant, beyond that a scaling fact will be applied to the temp. in K.
i.e. T1=m1*T(K)+c1
T1=m1*T(K)+c1
T2=m2*T(K)+c2
at first temperature
T(K1)=T(K1)
#1) m1*T(K1)+c1=14
#2) m2*T(K1)+c2=36
T(K2)=T(K2)
#3) m1*T(K2)+c1=133
#4) m2*T(K2)+c2=87
#4-#2=m2(T(K2)-T(K1))=87-36=51
#3-#1=m1(T(K2)-T(K1))=133-14=119
m1=119/51*m2
The formula for converting is:
T2=(T1-14)*51/119+36
They will be equal at:
T1=(T1-14)*51/119+36
(1-51/119)*T1=36-14*51/119
T1=52.5 degrees
Formula can be simplified to
T2=T1*3/7+30
Answer:
Formula is: T2=T1*3/7+30
T2=T1 at 52.5 degrees
Cam
Hi Cam ...
that is correct :)
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