Last Digit
posted by ToM at
11:55 PM
Monday, February 22, 2010
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3 Comments:
9.
The powers of 7 cycle through 7, 9, 3, 1, 7, . . .
Divide 38383822458 by 4 and the remainder is 2.
This corresponds to the second power of 7 which is 49, and so the required power also ends in 9.
Wiz. Nice one. I've responded to your comment under "six take a test".
The FIRST digit is 2, and there are 283816788925 digits total. :-)
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