Friday, March 5, 2010

The Game of Cards

The Puzzlarian Tavern offers various games to maintain the interest of their drinkers ... oops, I meant patrons. Four of the regular customers are engaged in a game of cards.

(in this game, ace is 1, all numbered cards are their number value, jack is 11, queen is 12, and king is 13)

Each player is holding 3 cards ... one heart, one club, and one spade.

a) the player holding the 4 of clubs is also holding a spade whose value is higher than that held by the man with the 3 of hearts

b) Knightmare has a spade whose value is 3 lower than that held by Cam, who has a heart with a value more than 3 lower than the club he is holding.

c) the player with the 7 of clubs and the 6 of spades has a heart whose value is 5 higher than the heart held by Ross.

d) the spade Chris has, is a higher value than his club, but a lower value than his heart.


Name the 3 cards in each player's hand.

(amendment: clue b - after the apostrophe, should read "who has heart with a value more than 3 lower" ... clue b has been corrected)
(Cards held:
Hearts: A, 3, 8, K
Clubs: 2, 4, 7, J
Spades: 5, 6, 9, Q)

15 Comments:

Blogger Knightmare said...

good...this is a hard one :)

I'll try it later,after the aid of alcohol.

March 5, 2010 9:03 PM  
Blogger Knightmare said...

seems to be something missing

knight:7-c,6-s,8-h
Chris:4-c,7-s,9-h
Cam:5-c,9-s,2-h
Ross?-c,4-s,3-h

March 5, 2010 9:51 PM  
Blogger Zaux said...

Knightmare...
sorry buddy ... not right

March 5, 2010 10:18 PM  
Blogger Knightmare said...

it doesn't follow the rules in the question?

March 5, 2010 10:39 PM  
Blogger Zaux said...

Knightmare ...
you got your hand right ... but you could see your hand :)

March 6, 2010 9:14 AM  
Blogger Knightmare said...

Cam:9-s,1-h,4-c
Ross:3-h

can't get any more
the question isn't missing a rule/clue is it?

March 6, 2010 1:49 PM  
Blogger Anonymous said...

Agreed that the problem is missing constraints/clues. I even tried to assume that all numbers has to be unique and there is still multiple solutions. As written, the only thing I can say for sure is:

Knightmare(C)=7
Knighmare(S)=6
Knightmare(H)=Ross(H)+5. Range:6-13.

Cam(C)=3+Cam(H) Range:4-13
Cam(S)=9
Cam(H)=Cam(C)-3 Range:1 - 10

Ross(C)= Range:1 to 13
Ross(S)=Range: 1 to 13
Ross(H)=Knightmare(H)-5 Range:1 to 8

Chris(C): Chris(C),Chris(C),>Chris(S) Range:3 to 13

Cam

March 6, 2010 6:35 PM  
Blogger Anonymous said...

Me gramR uhh gud lst post.

Believe it or not, english is my first language.

Cam

March 6, 2010 6:37 PM  
Blogger Zaux said...

I checked all the given info ... looks correct.

March 6, 2010 8:31 PM  
Blogger Zaux said...

this is a momentous event ... no one solved The Game of Cards.
Solution:

The man with the 7 of clubs and the 6 of spades isn't Ross (clue c)or Chris (clue d), so it's Knighmare (2) and Cam has the 9 of spades. Either Knightmare has the 8 and Ross has the 3 of hearts (3), or Knightmare has the king and Ross has the 8 of hearts; thus the 8 of hearts is held by either Knightmare or Ross. So Chris has the king of hearts(4), thus knightmare has the 8, and Ross has the 3 (3). So Cam has the ace of hearts and (2) jack of clubs. Ross does not have the queen of spades
(1), so Ross has the 5 of spades and Chris has the queen of spades. Ross has the 2 of clubs (1) and Chris has the 4 of clubs.

Recap:

Knightmare: 8 of hearts, 7 of clubs, and 6 0f spades

Chris: king of hearts, 4 of clubs, and queen of spades

Cam: ace of hearts, lack of clubs, and 9 of spades

Ross: 3 of hearts, 2 of clubs, and 5 of spades

March 6, 2010 10:19 PM  
Blogger Anonymous said...

So from following the solutions it is definitely assumed that there are no duplicate numbers, which wasn't stated in the problem.

But there is still something missing, otherwise the below is a valid solution (and there are more). Check it against the rules, it fits.

Knightmare(C)=7
Knighmare(S)=6
Knightmare(H)=10

Cam(C)=11
Cam(S)=9
Cam(H)=8

Ross(C)= 4
Ross(S)=12 or 13
Ross(H)=5

Chris(C): 1
Chris(S):2
Chris(H):3

Cam

March 7, 2010 12:20 AM  
Blogger Anonymous said...

From the wording of the solution it sounds to me like in the text or in the form of a picture, 12 or 13 cards are identified, (all different number values) and the suit of each card was identified somehow.

Cam

March 7, 2010 12:31 AM  
Blogger Zaux said...

Cam ...
thanks for your persistence. In clue b, I stated "3 lower" and it should have been "more than 3 lower"

March 7, 2010 5:40 AM  
Blogger Anonymous said...

Zaux,

Still something missing, even with the update... The following would be valid (can also swap 12 and 13 from Cam and Ross. Sure there are many more solutions):

Knightmare(C)=7
Knighmare(S)=6
Knightmare(H)=10

Cam(C)=13
Cam(S)=9
Cam(H)=8

Ross(C)= 4
Ross(S)=12
Ross(H)=5

Chris(C): 1
Chris(S):2
Chris(H):3

Almost positive that the original problem must have 12 or 13 cards identified, (all different number values) and the suit of each card was identified somehow. Likely they are shown in a picture, so it could easily be missed. That way it wouldn't be necessary to state that the number values must be different (which is crucial for a unique solution) and would explain why solution refers to such a limited set of cards for the solution path.


Cam

March 7, 2010 10:20 AM  
Blogger Zaux said...

Cam, I'm embarassed ... I see what they did ... the way they did it is not very clear, but try this additional info:

Hearts: A, 3, 8 K
Clubs: 2, 4, 7, J
Spades: 5, 6, 9, Q

Hope that's it!

March 7, 2010 8:09 PM  

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