Sunday, March 21, 2010

Number Sets 2

Below are 3 sets, each containing 3 numbers.
Determine the relationship between the numbers in the sets ...
then use that relationship to complete the last 3 sets:
(each ? is a digit)

10......62......310
6.......38......114
10......20.......20

4.......74......???
??......40.......40
8.......??......136

10 Comments:

Blogger Ragknot said...

Wow, this is a hard one. I give up!

March 21, 2010 6:54 PM  
Blogger Zaux said...

Just to clarify ...

There is one identical relationship between the first and second number of each set ... and there is one identical relaionship between the second and third number of each set ...

Is that correct?

March 21, 2010 8:03 PM  
Blogger Zaux said...

This post has been removed by the author.

March 21, 2010 8:04 PM  
Blogger Zaux said...

I obviously misunderstand the question ... I thought the relationship was the same between the first an second nuumner of each set ... can't be ... you can't take 10 and perform some function to get 62 .. and then take 10 and perform the same function and get 20.

I admit ... I'm confused

March 21, 2010 8:56 PM  
Blogger Ragknot said...

To clarify: There's a single relationship that connects the numbers. Once this relationship is found, the eureka moment should occur.

The eureka relationship can be expressed with three letters.

It like SUM, the first two would add up to the third. but SUM is not the right 3 letters.

March 21, 2010 9:49 PM  
Blogger Ragknot said...

More,

You might conclude that I multiply the first times the second and then divide by two. But the third one blows that idea.

But the relationship is not to complex. I think I remember learning it in the 3rd grade. But that was more that 50 years ago.

Maybe they don't teach it now, but they should.

March 21, 2010 10:10 PM  
Blogger Jin said...

Wow...this was a good one !!

The simple operation is LCM, though I must say it seems simple only AFTER cracking the problem ;)

4......74.........148
10....40.........40
8......17.........136

Other solutions could be: 20 or 40 for second set

34 or 68 for third set

Enjoyed it !

March 22, 2010 12:49 AM  
Blogger Ragknot said...

Congrats Jin, exactly right

Eureka LCM

These were fairly simple, but
a more general description follows.


To find either the Least Common Multiple (LCM) or Greatest Common Factor (GCF) of two numbers, you always start out the same way: you find the prime factorizations of the two numbers. Then you put the factors into a nice neat grid of rows and columns, and compare and contrast and take what you need.

http://www.purplemath.com/modules/lcm_gcf.htm

March 22, 2010 1:48 AM  
Blogger Eman said...

i got it the first and the third are the same idea but second is different
4 74 148
20 40 40
8 34 136

March 22, 2010 12:45 PM  
Blogger Ragknot said...

Yes, Eman, you can have different solutions for this problem.

For the second row you might have

2 40 40
4 40 40
5 40 40
8 40 40
10 40 40
20 40 40
40 40 40

Each of these fit the LCM pattern.

March 22, 2010 3:17 PM  

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