## Raising the Bar for Children

Old, but gold… A man walks into a bar on Main Street, orders a drink, and starts chatting with the bartender. After a while, he learns that the bartender has three children. “How old are your children?” he asks. “Well,” replies the bartender, “the product of their ages is 72.” The man thinks for a moment and then says, “That’s not enough information.” “All right,” continues the bartender, “if you go outside and look at the building number posted over the door to the bar, you’ll see the sum of their ages.” The man steps outside, and after a few moments he reenters and declares, “Still not enough!” The bartender smiles and says, “My youngest just loves strawberry ice cream.” The man says that he now knows the children’s ages.

How old are the children and what is the bar’s address?

April 15th, 2014 at 5:41 am

72 = 2*2*2*3*3

Possible ages: 2,4,9 or 2,6,6 or 2,2,18 or 2,3,12 or 3,4,6 or 3,3,8,

Sum of ages: 15 14 22 17 13 14

If not enough therefore must have same 2: Sum is 14

My youngest = only one youngest

Therefore their ages are

2, 6 and 6.

April 15th, 2014 at 6:55 am

2+6+6 = 14

possible age combinations:

1 1 72

1 2 36

1 3 24

1 4 18

1 6 12

1 8 9

2 2 18

2 3 12

2 4 9

2 6 6

3 3 8

3 4 6

Since their sum wasn’t enough information, look for at least 2 combinations with the same sum. 2+6+6 and 3+3+8 each add to 14. Since “my youngest” was stated, there is a definite ‘youngest’, so they cannot be the same age. Meaning 3+3+8 is out, and 2+6+6 is our answer.

Oh twins.

April 15th, 2014 at 7:56 am

Too easy, I guess…