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Easy Maths Primer

Posted by Karl Sharman on August 19, 2014 – 12:27 am

The prime 41, can be written as the sum of six consecutive primes:

41 = 2 + 3 + 5 + 7 + 11 + 13

This is the longest sum of consecutive primes that adds to a prime below one-hundred.

The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953.

Which prime, below one-million, can be written as the sum of the most consecutive primes?

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3 Responds so far- Add one»

  1. 1. jan jansen Said:

    997651, 543 terms

  2. 2. jan jansen Said:

    for 10 million
    9951191,1587 terms

  3. 3. Chris Said:

    Hi Karl. Sadly another number cruncher only problem. But as usual, in checking for a cunning method, I’ve read about all sorts of wonderful maths. I found confirmation of Jan’s first post, but I have only made a semi-pathetic attempt at confirming it/them for myself.

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