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## Easy Maths Primer

Posted by Karl Sharman on August 19, 2014 – 12:27 am

The prime 41, can be written as the sum of six consecutive primes:

41 = 2 + 3 + 5 + 7 + 11 + 13

This is the longest sum of consecutive primes that adds to a prime below one-hundred.

The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953.

Which prime, below one-million, can be written as the sum of the most consecutive primes?

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This post is under “Tom” and has 3 respond so far.

### 3 Responds so far- Add one»

1. 1. jan jansen Said：

997651, 543 terms

2. 2. jan jansen Said：

for 10 million
9951191,1587 terms

3. 3. Chris Said：

Hi Karl. Sadly another number cruncher only problem. But as usual, in checking for a cunning method, I’ve read about all sorts of wonderful maths. I found confirmation of Jan’s first post, but I have only made a semi-pathetic attempt at confirming it/them for myself.

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