Easy and True
I did this easy and true computation about 3 years ago.
To compute X, when X is on both sides of the equation,
but one side, the X, and maybe other numbers are in a Log,
you can easily compute the X easy.
Example, find the X to several digits when X=10+Log(20*X).
Just guess an X and compute the =10+Log(20*X).
Then use the solution for the next X as a new loop.
Then if you guess the first X as 1 to 1000 the X can be
computed to many digits in about 8 loops.
So compute this X to about 10 digits.
Example: First use any number for the first X.
If you use X=1 for the first X the first loop will give 11.301029995664
If you use X=100 for the first X the first loop will give 13.301029995664
Then use the first loop X, for the next X loop. After some loops the
X will stop changing. But if you need about 100 digits, it might take
about 30 loops