I agree. The mode is the most common number, and is only defined if there is a unique choice for it. The median is the middle number. The mean is the the arithmetic average value.

Let the numbers be a ≤ b ≤ c ≤ d ≤ e. Immediately see that c = 5. The mode
(1+1+5+d+e)/5 = 4 => d+e = 13. d and e must be > 5 and so d = 6 and e = 7.

…aaargh. You can have more than one mode. Fortunately there is only one this time. Also if there are an even number of values, the median is the arithmetic average of the middle two.

numbers are 1,1,5,6,7. mode being 1 and median 5 was a complete give away on the first 3 numbers. to find the remaining ….mean of 5 nos. 4 so sum being 20…remainign 2 numbers need to hv sum 13. hence 6,7

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January 6th, 2011 at 4:03 pm

1,1,5,6,7

January 6th, 2011 at 4:03 pm

1 1 5 6 7

January 6th, 2011 at 4:54 pm

I agree. The mode is the most common number, and is only defined if there is a unique choice for it. The median is the middle number. The mean is the the arithmetic average value.

Let the numbers be a ≤ b ≤ c ≤ d ≤ e. Immediately see that c = 5. The mode

(1+1+5+d+e)/5 = 4 => d+e = 13. d and e must be > 5 and so d = 6 and e = 7.

January 6th, 2011 at 4:57 pm

…aaargh. You can have more than one mode. Fortunately there is only one this time. Also if there are an even number of values, the median is the arithmetic average of the middle two.

January 7th, 2011 at 3:56 am

numbers are 1,1,5,6,7. mode being 1 and median 5 was a complete give away on the first 3 numbers. to find the remaining ….mean of 5 nos. 4 so sum being 20…remainign 2 numbers need to hv sum 13. hence 6,7

January 7th, 2011 at 7:38 pm

The numbers are 1,1,5,6, & 7. Thanks for the teaser. That is probably one of the only ones I could understand. lol.

January 7th, 2011 at 9:40 pm

1,1,5,6,7… I got that in less than 10 seconds, it seemed too easy though.

January 8th, 2011 at 2:31 am

Sorry it was so easy Bree – Chris and Buffon explained it. I placed the question to see if anyone went with average instead of median.

January 14th, 2011 at 11:10 pm

1,1,5,6&7