Another prime mess
Evaluate Product((p² + 1)/(p² – 1)) where the product is over all the primes, p.
The answer is about 10% less than e.
The primes are: 2,3,5,7,11,13,…
I don’t know how to do it (but I haven’t really tried yet). It may require advanced mathematics (but I really don’t know if that’s the case). It was discovered by one of the most brilliant mathematicians that ever walked this planet.